
Yeh chapter electrostatic force aur electric field ke baare mein aur gehri samajh provide karta hai. Humein electric potential, potential difference, equipotential surfaces, aur capacitors ke concepts padhne ko milte hain. Ye sab concepts aage ke chapters ke liye bhi bahut important hain.
Here we have provided NCERT Solution for Class 12 भौतिकी विज्ञानI in hindi Language, Just select the chapters below to get solution of the same:
वैधुत आवेश तथा क्षेत्र
स्थिर वैधुत विभव तथा धारिता
विद्युत धारा
गतिमान आवेश और चुंबकत्व
चुंबकत्व एवं द्रव्य
वैधुत चुंबकीय प्रेरण
प्रत्यावर्ती धारा
वैधुत चुंबकीय तरंग
Is chapter ke solutions mein hum har ek question ko step-by-step solve karenge, jisse aapko fundamental concepts clear ho jaayein. Humein sabse pehle electric potential ki definition samajhni hogi.
Electric potential kisi point par wo work hai jo ek unit positive charge ko infinity se us point tak lane ke liye karna padta hai. Iska SI unit Volt hai. Formula: V = kQ/r. Iski madad se hum kisi bhi charge distribution ke kaaran kisi point par potential nikal sakte hain.
Equipotential surfaces wo surfaces hain jahaan har point par potential constant hota hai. Electric field lines hamesha in surfaces ke perpendicular hote hain.
Capacitor do conductors ka system hota hai jo charge store karta hai. Capacitance (C) charge storing capacity ko denote karta hai. C = Q/V. Parallel plate capacitor ka formula: C = ε₀A/d, jahaan A plate area hai aur d separation hai.
Capacitors ko series aur parallel mein combine kiya ja sakta hai.
Ek charged capacitor mein stored energy: U = (1/2)CV² = (1/2)Q²/C = (1/2)QV. Yeh energy electric field mein store hoti hai. Agar dielectric material introduce kiya jaaye, toh capacitance increase ho jaati hai. C = kC₀, jahaan k dielectric constant hai.
Chapter ke end mein diye gaye numerical problems ko solve karte waqt in steps ko follow karein: (1) Given data ko note karein. (2) Relevant formula identify karein. (3) Values substitute karein. (4) Unit ke saath final answer likhein. For example, two charges +5μC aur -3μC, 16 cm ki distance par rakhe hain. Unke midpoint par electric potential nikalna hai. Solution: V_total = k[q1/(r/2) + q2/(r/2)]. Values daalne par answer aayega 2.25 x 10^5 V.
In solutions ko acche se practice karna board exams ke liye bahut helpful rahega. Har concept ko diagram ke saath samajhne ki koshish karein.