
Trigonometric Functions ka ye chapter Class 11 ke liye bahut hi mahatvapurn hai. Yahaan par hum angles aur triangles ke beech ke sambandhon ko padhenge. Is chapter mein students ko milenge:
Niche diye gaye detailed solutions se aap har concept ko asani se samjh paayenge.
Here we have provided NCERT Solution for Class 11 गणितII in hindi Language, Just select the chapters below to get solution of the same:
सरल रेखाएँ
शांकव परिच्छेदन
त्रिविमीय ज्यामिति का परिचय
सीमा और अवकलज
गणितीय विवेचन
सांख्यिकी
प्रायिकता
Yeh solutions Class 11 Maths ke Chapter 3 ke liye designed kiye gaye hain. Har question ko step-by-step explain kiya gaya hai taki students deeply concept ko grasp kar saken. Solutions Hinglish language mein hain jisse samajhna aasan ho.
Sabse pehle, hum trigonometric ratios ke bare mein padhenge. Right-angled triangle mein, teen basic ratios hote hain: sine, cosine, aur tangent. Inhe aise define karte hain:
Inhi se hum derive karte hain cosec, sec, aur cot ratios. Ye sabhi ratios ek dusre se related hain through trigonometric identities.
Angles ko measure karne ke do common tarike hain: degrees aur radians. Ek complete circle 360 degrees ya 2π radians ke barabar hota hai. Conversion formula ye hai: radians = (π/180) × degrees. Is conversion ka use karke hum problems solve karte hain.
Example: 60 degrees ko radians mein convert karenge.
Solution: Radians = (π/180) × 60 = π/3 radians.
Har trigonometric function ka apna unique graph hota hai. Sine aur cosine functions periodic hote hain with period 2π. Tangent function ka period π hota hai. In graphs ko samajhna important hai kyunki ye functions ki behavior dikhate hain.
Graph plotting karte waqt hum domain aur range par dhyan dete hain. For example, sine function ki range -1 se 1 tak hoti hai.
Kuch basic identities jo har student ko yaad rakhni chahiye:
In identities ka use karke hum complex problems ko simplify kar sakte hain. Practice se ye formulas automatically yaad ho jaati hain.
Ab hum kuch important NCERT problems ke solutions dekhenge.
Problem: Agar sin A = 3/5, to cos A aur tan A ki value find kariye.
Solution: Hum jaante hain sin²A + cos²A = 1
Isliye, cos²A = 1 - sin²A = 1 - (9/25) = 16/25
So, cos A = 4/5 (positive lenge kyunki A first quadrant mein hai as per question)
Ab tan A = sin A / cos A = (3/5) / (4/5) = 3/4
In solutions se aapko trigonometric functions ke concepts clear ho jaayenge. Har step ko carefully follow karein aur khud se practice karein. Confidence ke saath apne exams ki taiyaari karein.