Class 10 Maths NCERT Solutions (Samadhan)

Yeh page aapko Class 10 NCERT Maths book ke kuch important chapters ke solutions provide karta hai. Humein pata hai ki concepts ko clear karna zaroori hai, isliye humne solutions ko simple steps mein explain kiya hai.

Kya Milega Ismein?

• Chapter 4 - Quadratic Equations ke kuch mukhya prashn
• Chapter 5 - Arithmetic Progression se related problems
• Chapter 6 - Triangles ke proofs aur applications

Links for Chapter-wise Download NCERT Solution for Class 10 गणित in hindi Language

Here we have provided NCERT Solution for Class 10 गणित in hindi Language, Just select the chapters below to get solution of the same:

बहुपद

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पृष्ठीय क्षेत्रफल और आयतन

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प्रायिकता

Class 10 Maths NCERT Detailed Solutions

Niche diye gaye solutions ko padhne se pehle, recommend kiya jaata hai ki aap apni NCERT textbook se related concepts aur formulas revise kar lein. Har solution mein logical steps follow kiye gaye hain.

Chapter 4: Quadratic Equations (Dvighat Samikaran)

Quadratic equations ka general form hota hai ax² + bx + c = 0. Ismein 'a' zero nahi ho sakta. Solutions find karne ke liye hum factorization method, completing the square, ya phir quadratic formula use karte hain.

Example Problem: Solve the equation 2x² - 5x + 3 = 0 using factorization.

Solution:
1. Equation ko likho: 2x² - 5x + 3 = 0.
2. Middle term ko break karo: 2x² - 2x - 3x + 3 = 0.
3. Common factor lein: 2x(x - 1) -3(x - 1) = 0.
4. Ab, (x - 1)(2x - 3) = 0.
5. Iska matlab, x - 1 = 0 ya 2x - 3 = 0.
6. Final answer: x = 1 ya x = 3/2.

Chapter 5: Arithmetic Progression (Samantar Shreni)

Arithmetic Progression (AP) mein consecutive terms ka difference constant hota hai. Is constant difference ko common difference (d) kehte hain. 'n'th term find karne ka formula hai: a_n = a + (n-1)d.

Example Problem: Find the 10th term of the AP: 2, 5, 8, 11,...

Solution:
1. Pehla term, a = 2.
2. Common difference, d = 5 - 2 = 3.
3. Formula use karo: a_10 = a + (10-1)d.
4. Values put karo: a_10 = 2 + (9)*3.
5. Calculation: 2 + 27 = 29.
6. Isliye, 10th term 29 hai.

Chapter 6: Triangles (Tribhuj)

Is chapter mein hum triangles ki similarity aur congruence ke rules padhte hain. Important theorems jaise Basic Proportionality Theorem (Thales Theorem) aur Pythagoras Theorem ka use karna seekhte hain.

Key Concepts for Problem Solving:

• Similar Triangles: Agar do triangles ke corresponding angles equal hon aur unki sides proportional hon, toh triangles similar hote hain. (AAA, SSS, SAS similarity criteria).
• Pythagoras Theorem: Right-angled triangle mein, (hypotenuse)² = (base)² + (perpendicular)².

Example Problem (Basic Proportionality Theorem): Ek triangle ABC hai jismein DE line BC ke parallel hai. Agar AD = 2 cm, DB = 3 cm, aur AE = 4 cm diya gaya hai, toh EC find karo.

Solution:
1. Thales Theorem ke according: AD/DB = AE/EC.
2. Values put karo: 2/3 = 4/EC.
3. Cross multiply karo: 2 * EC = 4 * 3.
4. Isse milega: 2EC = 12.
5. Dono side ko 2 se divide karo: EC = 6 cm.
6. Final answer: EC ki length 6 cm hai.

In solutions ko practice karke aap concepts ko better understand kar sakte hain. Hamesha try karein ki aap khud se problem solve karein, phir solution se apna answer cross-check karein.