
Yeh page ek important NCERT Exemplar question aur uska detailed solution provide karta hai, jo Class 10 Maths ke chapter 'Quadratic Equations' se liya gaya hai. Isse students apne concepts clear kar sakte hain aur board exam ki taiyari acche se kar sakte hain.
Is question mein hum quadratic equation ke roots ki nature (real, equal, imaginary) find karenge.
Here we have provided NCERT Exemplar Questionfor Class 10 Maths in hindi Language, Just select the chapters below to get Exemplar Solution of the same:
Yeh question Class 10 Maths NCERT Exemplar book Chapter 4 'Quadratic Equations' se liya gaya hai. Yeh question board exams mein frequently pucha jata hai aur iska concept bahut important hai.
Question: Find the nature of the roots of the following quadratic equation. If the real roots exist, find them: 2x² - 6x + 3 = 0
Chalo is question ko step-by-step solve karte hain:
Hamare paas quadratic equation hai: 2x² - 6x + 3 = 0
Standard form ax² + bx + c = 0 ke according:
a = 2, b = -6, c = 3
Discriminant formula hai: D = b² - 4ac
D = (-6)² - 4 × 2 × 3
D = 36 - 24
D = 12
Kyunki D > 0 (D positive hai), isliye:
• Roots real aur distinct honge
• Roots unequal honge
• Roots do honge
Quadratic formula hai: x = [-b ± √D] / 2a
x = [6 ± √12] / (2 × 2)
x = [6 ± 2√3] / 4
x = [3 ± √3] / 2
Isliye, roots hain:
x₁ = (3 + √3) / 2
x₂ = (3 - √3) / 2
Nature of roots: Real and distinct
Real roots: (3 + √3)/2 and (3 - √3)/2
1. Direct formula application: Yeh question discriminant aur quadratic formula dono ka use karna sikhata hai.
2. Concept clarity: Nature of roots ka concept clear ho jata hai.
3. Board exam pattern: Aise questions frequently board exams mein aate hain.
4. Step marking: Step-by-step solution se full marks milte hain.
• Sign mistake: b = -6 hai, iska square karte time sign ka dhyaan rakhna.
• Calculation error: 4ac calculate karte time 4 × 2 × 3 = 24, isme galti na karen.
• Simplification: √12 = 2√3 simplify karna na bhoolen.
• Final answer: Roots ko simplest form mein likhna zaroori hai.
1. Find nature of roots: 3x² - 4√3x + 4 = 0
2. Find roots if real: x² + 7x + 10 = 0
3. Check if roots are equal: 2x² - 3x + 5 = 0
• Discriminant: D = b² - 4ac
• Nature of roots: D > 0 (real, distinct), D = 0 (real, equal), D < 0 (no real roots)
• Quadratic formula: x = [-b ± √D] / 2a
• Standard form: ax² + bx + c = 0, where a ≠ 0
Agar aap board exam mein aisa question solve karte hain to marks is tarah milte hain:
• Correct formula application: 1 mark
• Correct discriminant calculation: 1 mark
• Correct nature determination: 1 mark
• Correct roots calculation: 1 mark
• Final answer: 1 mark
Total: 5 marks ka question. Isliye har step sahi likhna zaroori hai.
1. Always write given equation clearly.
2. Identify coefficients a, b, c correctly.
3. Calculate discriminant carefully without sign mistakes.
4. Determine nature based on D value.
5. Use quadratic formula only if D ≥ 0.
6. Simplify the final answer properly.
7. Always check your solution by putting values back in original equation.
Yeh NCERT Exemplar question practice karke aap Quadratic Equations chapter mein confident ho jaoge. Board exam mein aise questions regularly aate hain, isliye iska solution acche se samajh lena chahiye.